\binom83 = \frac8!3!(8-3)! = \frac8 \times 7 \times 63 \times 2 \times 1 = 56 - RTA
Understanding Binomial Coefficients: A Deep Dive into $\binom{8}{3} = 56$
Understanding Binomial Coefficients: A Deep Dive into $\binom{8}{3} = 56$
When exploring the world of combinatorics, few expressions are as fundamental and widely used as the binomial coefficient $\binom{n}{k}$. This mathematically elegant formula counts the number of ways to choose $k$ items from a set of $n$ items without regard to order. Today, we’ll unpack the meaning and calculation of $\binom{8}{3}$, revealing why this number holds key importance in mathematics, statistics, and everyday problem-solving.
What Is $\binom{8}{3}$?
Understanding the Context
$\binom{8}{3}$ represents the number of combinations of 8 items taken 3 at a time. It answers the question: In how many different ways can 3 items be selected from a group of 8 unique items?
For example, if you’re selecting a team of 3 players from 8 candidates, $\binom{8}{3} = 56$ means there are 56 distinct combinations possible. This concept is essential in fields like probability, statistics, genetics, computer science, and project planning—where selection without replacement matters.
The Formula: $\binom{n}{k} = \dfrac{n!}{k!(n-k)!}$
The binomial coefficient is formally defined as:
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Key Insights
$$
\binom{n}{k} = \frac{n!}{k!(n - k)!}
$$
Where:
- $n!$ (n factorial) is the product of all positive integers up to $n$:
$n! = n \ imes (n-1) \ imes (n-2) \ imes \cdots \ imes 1$
- $k!$ is the factorial of $k$, and
- $(n - k)!$ is the factorial of the difference.
Plugging in $n = 8$ and $k = 3$:
$$
\binom{8}{3} = \frac{8!}{3!(8-3)!} = \frac{8!}{3! \cdot 5!}
$$
Step-by-Step Calculation
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To better understand, let's break down the calculation step-by-step:
-
Write out $8!$:
$8! = 8 \ imes 7 \ imes 6 \ imes 5 \ imes 4 \ imes 3 \ imes 2 \ imes 1$ -
Write out $5!$ (since $8 - 3 = 5$):
$5! = 5 \ imes 4 \ imes 3 \ imes 2 \ imes 1 = 120$ -
Write out $3!$:
$3! = 3 \ imes 2 \ imes 1 = 6$ -
Substitute into the formula:
$$
\binom{8}{3} = \frac{8 \ imes 7 \ imes 6 \ imes 5!}{3! \ imes 5!}
$$ -
Cancel $5!$ in numerator and denominator:
$\binom{8}{3} = \frac{8 \ imes 7 \ imes 6}{3!} = \frac{8 \ imes 7 \ imes 6}{3 \ imes 2 \ imes 1}$
-
Simplify the denominator:
$3 \ imes 2 \ imes 1 = 6$ -
Calculate the final value:
$$
\frac{8 \ imes 7 \ imes 6}{6} = 8 \ imes 7 = 56
$$
So, $\binom{8}{3} = 56$.
