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๐ฐ Therefore, the largest possible value of \( v \) is \(\boxed{12}\).
๐ฐ How many positive 3-digit numbers are divisible by 9 and end with the digit 3?
๐ฐ We seek 3-digit numbers divisible by 9 and ending in 3. A number divisible by 9 has its digit sum divisible by 9. Also, the number must end in 3, so let it be of the form \( 100a + 10b + 3 \), where \( a \in \{1,2,\dots,9\} \), \( b \in \{0,1,\dots,9\} \), and the number is divisible by 9.
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