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\( x^2 + (x+1)^2 = 145 \) → \( x^2 + x^2 + 2x + 1 = 145 \) → \( 2x^2 + 2x - 144 = 0 \).
Divide by 2: \( x^2 + x - 72 = 0 \) → \( (x + 9)(x - 8) = 0 \).
So \( x = 8 \), larger integer is 9.

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