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📅 May 10, 2026 👤 scraface

May 10, 2026

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Using the difference of squares in the denominator:
rac{3(\sqrt{7} + \sqrt{2})}{5} = rac{3\sqrt{7} + 3\sqrt{2}}{5}
Final simplified form:
oxed{rac{3\sqrt{7} + 3\sqrt{2}}{5}}
Question: Let $f(x) = 2x^2 - 3x + 1$ and $g(x) = \sqrt{x + 4}$. What i...
Solution: First evaluate $f(2)$:
f(2) = 2(2)^2 - 3(2) + 1 = 8 - 6 + 1 = 3
Now evaluate $g(f(2)) = g(3)$:
g(3) = \sqrt{3 + 4} = \sqrt{7}
oxed{\sqrt{7}}

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