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Home » FÃ¼r $ x = 5 $: $ x \mid y \Rightarrow y \mid 5 $? - RTA

FÃ¼r $ x = 5 $: $ x \mid y \Rightarrow y \mid 5 $? - RTA

📅 May 9, 2026 👤 scraface

May 09, 2026

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Average speed: \(\frac{500}{5} = 100\) km/h.
A quadratic equation \(2x^2 - 3x - 2 = 0\) is given. Find its roots.
Using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\...
Here, \(a = 2\), \(b = -3\), \(c = -2\).
\(x = \frac{3 \pm \sqrt{(-3)^2 - 4 \times 2 \times (-2)}}{4}\).
\(x = \frac{3 \pm \sqrt{9 + 16}}{4}\).
\(x = \frac{3 \pm \sqrt{25}}{4}\).
\(x = \frac{3 \pm 5}{4}\).
Roots: \(x = 2\) and \(x = -\frac{1}{2}\).
#### 2, \(-\frac{1}{2}\)Question: A weather radar detects a storm fron...

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