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Home » Gina Wilson’s Unit 2 Homework 5: The ALGEBRA TRICK That’s Fighting Back — Trial #5! - RTA

Gina Wilson’s Unit 2 Homework 5: The ALGEBRA TRICK That’s Fighting Back — Trial #5! - RTA

📅 May 10, 2026 👤 scraface

May 10, 2026

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$\sin z = 1/2$ â $z = 30^\circ, 150^\circ$.
All four satisfy the equation.
Thus, the solutions are $30^\circ, 90^\circ, 150^\circ, 270^\circ$.
Question: Compute $(\cos 15^\circ + i \sin 15^\circ)^6$ and express th...
Solution: By De Moivre's Theorem:
oxed{i}Question: What is the smallest positive integer whose cube end...
Solution: We seek the smallest positive integer $ n $ such that $ n^3...
First, modulo $8$:
$ n^3 \equiv 888 \pmod{8} $. Since $888 \div 8 = 111$, $888 \equiv 0 \...
So $ n^3 \equiv 0 \pmod{8} $, which implies $ n \equiv 0 \pmod{2} $, a...

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