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📰 z^4 + 4z^2 + 4 = (z^2 + 2)^2 = 0 📰 So indeed, \( (z^2 + 2)^2 = 0 \), so roots are \( z = \pm i\sqrt{2} \), each with multiplicity 2. But the **set of distinct roots** is still two: \( i\sqrt{2}, -i\sqrt{2} \), each included twice. But the problem asks for **the sum of the real parts of all complex numbers \( z \)** satisfying the equation. Since real part is 0 for each, even with multiplicity, the sum is still \( 0 + 0 = 0 \). 📰 Alternatively, interpret as sum over all **solutions** (with multiplicity or not)? But in algebraic contexts like this, unless specified, we consider distinct roots or with multiplicity. But multiplicity doesn't affect real part — each root contributes its real part once in evaluation, but the real part function is defined per root. However, in such symmetric cases, we sum over distinct roots unless told otherwise. 📰 These Bible Clipart Graphics Are Taking Social Media By Stormyou Cant Miss Them 2116951 📰 A Cone Has A Radius Of 3 Cm And A Height Of 4 Cm What Is Its Volume Use Pi Approx 314 30629 📰 Joining The Thieves Guild Oblivion 619156 📰 Youll Never Guess Whats Hidden Under Biloxis Surfaceexplore These Secret Gems 5671411 📰 How To Fix Sleep Apnea 6046956 📰 Green Rivers Silent Murderer The Unsolved Horror That Shocks The Heart 2684419 📰 Dinner Dreams Just Got Cheaper Free Cooking Games To Slay Your Next Meal 2896215 📰 The Stunning Symbol Of Tunisias Flag That Will Blow Your Mind 1827728 📰 Nvds Stock Alert Experts Say This Tech Giant Will Revolutionize Investing 278016 📰 Why Everyones Missing The Real Source Of The Greatest Proverbs The Untold Truth 4005499 📰 You Wont Believe What Attackers Say On The Most Haunted Tv Screen 4204650 📰 Skip The Hop Unlock The Real Fun Youve Been Missing 405879 📰 3 United Rental Stock Surge How This Trend Could Double Your Investment Overnight 4032616 📰 Irb Submission 6028761 📰 John Bell Hood 8298524