Question**: A bank offers a compound interest rate of 5% per annum, compounded annually. If you deposit $1000, how much will the amount be after 3 years? - RTA
Title: How to Calculate Compound Interest: $1,000 at 5% Annual Rate Grows to How Much After 3 Years?
Title: How to Calculate Compound Interest: $1,000 at 5% Annual Rate Grows to How Much After 3 Years?
Meta Description:
Learn how compound interest works with a 5% annual rate compounded annually. Discover the future value of a $1,000 deposit over 3 years, and understand the true power of compound growth.
Understanding the Context
Question: A bank offers a compound interest rate of 5% per annum, compounded annually. If you deposit $1,000, how much will the amount be after 3 years?
If you’ve ever wondered how your savings grow when earning compound interest, this real-world example shows exactly how much your $1,000 deposit will grow in just 3 years at a 5% annual rate, compounded yearly.
Understanding Compound Interest
Compound interest is interest calculated on the initial principal and the accumulated interest from previous periods. Unlike simple interest, which is earned only on the original amount, compound interest enables your money to grow more rapidly over time — a powerful advantage for long-term savings and investments.
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Key Insights
The Formula for Compound Interest
The formula to calculate compound interest is:
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
Where:
- \( A \) = the amount of money accumulated after n years, including interest
- \( P \) = principal amount ($1,000 in this case)
- \( r \) = annual interest rate (5% = 0.05)
- \( n \) = number of times interest is compounded per year (1, since it’s compounded annually)
- \( t \) = time the money is invested or borrowed for (3 years)
Applying the Values
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Given:
- \( P = 1000 \)
- \( r = 0.05 \)
- \( n = 1 \)
- \( t = 3 \)
Plug these into the formula:
\[
A = 1000 \left(1 + \frac{0.05}{1}\right)^{1 \ imes 3}
\]
\[
A = 1000 \left(1 + 0.05\right)^3
\]
\[
A = 1000 \ imes (1.05)^3
\]
Now calculate \( (1.05)^3 \):
\[
1.05^3 = 1.157625
\]
Then:
\[
A = 1000 \ imes 1.157625 = 1157.63
\]
Final Answer
After 3 years, your $1,000 deposit earning 5% compound interest annually will grow to $1,157.63.
This means your investment has grown by $157.63 — a clear demonstration of how compounding accelerates wealth over time.
