Question: Find the $ y $-intercept of the line that passes through the points $ (1, 3) $ and $ (4, 9) $. - RTA
Find the $ y $-Intercept of the Line Passing Through Points $ (1, 3) $ and $ (4, 9) $ — A Core Concept in Understanding Linear Relationships
Find the $ y $-Intercept of the Line Passing Through Points $ (1, 3) $ and $ (4, 9) $ — A Core Concept in Understanding Linear Relationships
Have you ever wondered how math connects dots on a graph to reveal real-world patterns? One key concept is the $ y $-intercept — the point where the line crosses the vertical axis. It’s not just a theory; it shows up in everything from budgeting to income projections. Take the line defined by $ (1, 3) $ and $ (4, 9) $. Curious about how to find where this line meets the $ y $-axis? This simple question opens the door to understanding slope, prediction, and data trends—critical for anyone navigating financial planning, career data, or educational growth metrics across the United States.
Understanding the Context
Why the $ y $-Intercept Matters in Everyday Life
Right now, more people than ever are relying on clear data insights in daily decision-making—whether tracking monthly savings, analyzing employment growth, or understanding performance curves in education or income. The $ y $-intercept reveals the baseline value: what’s expected when input is zero. For example, a startup might estimate user count at launch (y-intercept) before growth trends take hold (slope). Similarly, a student analyzing salary progression might use this intercept as a starting benchmark. This concept is not abstract—it shapes forecasting, planning, and informed choices.
Understanding how to calculate this intercept demystifies linear patterns embedded in real-world data, empowering users to engage confidently with graphs, tables, and digital tools used widely in US workplaces, schools, and public forums.
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Key Insights
How to Find the $ y $-Intercept: A Clear, Step-by-Step Approach
The $ y $-intercept is found using two key points and a basic formula from linear algebra. For the line through $ (1, 3) $ and $ (4, 9) $, start by calculating the slope: rise over run.
Slope $ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{9 - 3}{4 - 1} = \frac{6}{3} = 2 $.
Then use point-slope form $ y - y_1 = m(x - x_1) $:
$ y - 3 = 2(x - 1) $
Simplify: $ y = 2x - 2 + 3 $
So $ y = 2x + 1 $
From this equation, the $ y $-intercept is the constant term: $ (0, 1) $. Alternatively, plug either point into $ y = mx + b $ to solve for $ b $. Using $ (1, 3) $:
$ 3 = 2(1) + b \Rightarrow b = 1 $
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Thus, the $ y $-intercept is $ (0, 1)