rac{(\sqrt{7} + \sqrt{3})^2}{(\sqrt{7})^2 - (\sqrt{3})^2} = rac{7 + 2\sqrt{21} + 3}{7 - 3} = rac{10 + 2\sqrt{21}}{4} = rac{5 + \sqrt{21}}{2}.

Sun, 10 May 2026 08:11:28 +0000

# Solving the Interesting Equation: Rac{(√7 + √3)²}{(√7)² − (√3)²} = (7 + 2√21 + 3)/(7 − 3) = (5 + √21)/2 Mathematics often hides elegant truths beneath layers of symbols and operations. One such intriguing relation involves radical expressions:
rac{(√7 + √3)²}{(√7)² − (√3)²} = (5 + √21)/2 In this article, we’ll break down this identity step-by-step, clarify implicit steps, and explore why this result—combining binomial expansion, algebraic simplification, and the difference of squares—is both elegant and instructive. ---