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Home » So, \(288\pi = \pi r^2 \times 12\). - RTA

So, \(288\pi = \pi r^2 \times 12\). - RTA

📅 May 10, 2026 👤 scraface

May 10, 2026

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📌 Original production: 240 units/hour. After 15% slowdown: 240 * 0.85 = <<240*0.85=204>>204 units/hour.

📌 In 4 hours: 204 * 4 = <<204*4=816>>816 units possible at max speed.

📌 But each unit needs 3 components. Assuming components are the bottleneck, and supply limits production, we find how many can be completed based on available components.

📌 Let’s assume initial component stock allows for *X* units before delay. But per hour, after slowdown: 204 units require 204 * 3 = 612 components per hour.

📌 But if supply drops by 20%, capacity is further reduced. However, production slowdown is already applied.

📌 The key is: with 816 units attempt, but components limited: suppose original component stock supports 816 * 3 = 2448 components.

📌 After 20% shortage, effective component pool: 2448 * 0.80 = 1958.4 → Less than needed.

📌 But under 15% slower operation, only 816 units can be assembled.

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