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Home » This Flawless 1-1 Fight | - RTA

This Flawless 1-1 Fight | - RTA

📅 May 9, 2026 👤 scraface

May 09, 2026

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So, LCM is $ 2^2 \cdot 3^2 = 4 \cdot 9 = 36 $.
Thus, the smallest positive integer divisible by both is $ \boxed{36}...
Question: What is the remainder when $ 2^{10} $ is divided by 7?
Solution: Compute $ 2^{10} = 1024 $. Divide 1024 by 7:
Use modular arithmetic: $ 2^3 = 8 \equiv 1 \mod 7 $, so $ 2^3 \equiv 1...
Thus, the remainder is $ \boxed{2} $.Question: What is the smallest fo...
To find the smallest four-digit number satisfying the given conditions...
\text{lcm}(12, 18) = \frac{12 \cdot 18}{\gcd(12, 18)} = \frac{216}{6}...
So, the number must be divisible by 36 and leave a remainder of 3 when...
n \equiv 0 \pmod{36}, \quad n \equiv 3 \pmod{7}

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