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Home » Thus, the total number of valid assignments is $ \boxed126000 $. - RTA

Thus, the total number of valid assignments is $ \boxed126000 $. - RTA

📅 May 11, 2026 👤 scraface

May 11, 2026

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📌 e 0 $. But since the equation holds only when $ a = 0 $, $ b $ can be any real number. However, the equation is identity only when $ a = 0 $, so no unique value of $ b $ exists unless further constraints are given.

📌 Thus, for nonzero $ a $, contradiction unless $ a = 0 $, implying $ b $ is arbitrary. But if we assume the identity holds for all $ a $, then the only way is $ 1 = 3 $, which is false.

📌 But if we treat the equation as an identity in $ a $ and $ b $, comparing both sides:

📌 e 0 $, contradiction. So the only consistent solution is $ a = 0 $, and $ b $ is arbitrary.

📌 However, if the problem implies the identity for all $ a $, its impossible. But if its for a specific $ a $, we cannot determine $ b $.

📌 Then $ b $ is not determined. But if we assume $ a

📌 e 0 $, no solution. But the question asks for $ b $, implying it exists.

📌 With $ a = 0 $, the equation becomes $ 0 = 0 $, true for any $ b $.

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