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📅 May 11, 2026 👤 scraface

May 11, 2026

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📌 Ahora sustituimos de nuevo en la identidad de la suma de cubos:

📌 x^3 + y^3 = (x + y)(x^2 - xy + y^2) = 6(20 - 8) = 6 \times 12 = 72

📌 Por lo tanto, el valor de $x^3 + y^3$ es $\boxed{72}$.

📌 Pregunta: Si $a + b = 10$ y $a^2 + b^2 = 58$, encuentra $a^3 + b^3$.

📌 Usamos la identidad para la suma de cubos:

📌 a^3 + b^3 = (a + b)(a^2 - ab + b^2)

📌 Sabemos $a + b = 10$ y $a^2 + b^2 = 58$. Para encontrar $ab$, usamos:

📌 10^2 = 58 + 2ab \implies 100 = 58 + 2ab \implies 2ab = 42 \implies ab = 21

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