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Home » \[ x = rac{6 \pm \sqrt36 - 32}2 \] - RTA

\[ x = rac{6 \pm \sqrt36 - 32}2 \] - RTA

📅 May 9, 2026 👤 scraface

May 09, 2026

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📌 Take the square root of both sides:

📌 \[ r = \sqrt{36} \]

📌 \[ r = 6 \]

📌 Therefore, the radius of the sphere is 6 units.

📌 Solve the quadratic equation \( 2x^2 - 4x - 6 = 0 \) using the quadratic formula \( x = rac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).

📌 The quadratic equation is \( 2x^2 - 4x - 6 = 0 \), where \( a = 2 \), \( b = -4 \), and \( c = -6 \).

📌 Calculate the discriminant:

📌 \[ b^2 - 4ac = (-4)^2 - 4(2)(-6) \]

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