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You Wont Believe Whats Hitting eBay TREND Today—Turn Read Now! - RTA

📅 May 2, 2026 👤 scraface

May 02, 2026

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The odd divisors of 180 are the divisors of $ 3^2 \cdot 5 = 45 $.
List all positive divisors of 45: $ 1, 3, 5, 9, 15, 45 $.
Now compute their sum:
+ 3 + 5 + 9 + 15 + 45 = 78
Thus, the sum of all positive odd divisors of 180 is $ \boxed{78} $.
Question: What is the remainder when $ 11071 + 11073 + 11075 + 11077 $...
Solution: We compute the sum modulo 8. First, reduce each term modulo...
\equiv 7 \pmod{8}, \quad 11073 \equiv 1 \pmod{8}, \quad 11075 \equiv 3...
Now sum them modulo 8:
+ 1 + 3 + 5 = 16 \equiv 0 \pmod{8}

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